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Q.

What is the de Broglie wavelength of an electron of energy 180 eV? Mass of electron =9×10−31 kg and Planck's constant =6.6×10−34 Js.

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a

0.5Å

b

0.9Å

c

1.3Å

d

1.8Å

answer is B.

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Detailed Solution

K=180eV=180×1.6×10−19J=2.88×10−17JNow λ=h2mK∴ λ=6.6×10−342×9×10−31×2.88×10−171/2=6.6×10−347.2×10−24=0.9×10−10m
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