What is the de Broglie wavelength of an electron of energy 180 eV? Mass of electron =9×10−31 kg and Planck's constant =6.6×10−34 Js.
0.5Å
0.9Å
1.3Å
1.8Å
K=180eV=180×1.6×10−19J=2.88×10−17J
Now λ=h2mK
∴ λ=6.6×10−342×9×10−31×2.88×10−171/2=6.6×10−347.2×10−24=0.9×10−10m