First slide

Doppler

Question

When a source and observer move away from each other with equal speeds, which is 1/10th of the speed of sound, the apparent frequency received by the observer is n. If the source and observer move towards each other with same equal speeds as before, the apparent frequency received by the observer will be nearly

Moderate

A

4n/5
B

2n/3
C

3n/2
D

5n/4

Solution

$w h e n t h e y ` m o v e a w a y f r o m e a c h o t h e r (\frac{v - v_{0}}{v + v_{s}}) f = n h e r e v_{0} = v_{s} = \frac{v}{10} s u b s t i t u t i n g w e g e t f = \frac{11}{9} n w h e n t h e y a p p r o a c h e a c h o t h e r n' = (\frac{v + v_{0}}{v - v_{s}}) f s o v i n g n' = \frac{11}{9} f = \frac{121}{81} n \approx \frac{3}{2} n$

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