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A wire having a linear mass density 5.0 x 10-3 kg/m is stretched between two rigid supports with a tension of 450 N. The wire resonates at a frequency of 420 Hz. The next higher frequency at which the same wire resonates is 480 Hz. The length of the wire is

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a

2.0 m

b

2.1 m

c

2.5 m

d

3 m

answer is C.

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Detailed Solution

Two consecutive frequencies are 420 Hz and 480 Hz. So the fundamental frequency will be 60 Hz.∴ 60 = 12×l4505×10-3 ⇒ l = 2.5 mHence (2).

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