An alkali metal hydride (NaH) reacts with diborane in ‘A’ to give a tetrahedral compound ‘B’ which is extensively used as reducing agent in organic synthesis. The compounds ‘A’ and ‘B’ respectively are
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a
CH3COCH3 and B3N3H6
b
(C2H5)2O and NaBH4
c
C2H6 and C2H5Na
d
C6H6 and NaBH4
answer is B.
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Detailed Solution
Diborane reacts with alkali metal hydride (NaH) in dry ether solvent to give sodium tetra hydrido borate.→ sodium tetra hydrido borate is used as strong reducing agent in organic synthesis.