CN⊝ ion is oxidised by a powerful oxidising agent to NO3⊝ and CO2 or CO32- depending on the acidity of the reaction mixture.CN⊖⟶CO2+NO3⊖+H⊕+ne−The number of (n) of electron involved in the process divided by 10 is
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answer is 3.
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Detailed Solution
After balancing the equation.15H2O+3CNΘ→3CO2+3NO3θ+30H⊕+30e−∴ Number of electrons=3010=3