Classical idea of redox reactions

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Question

${CN}^{⊝}$ ion is oxidised by a powerful oxidising agent to ${NO}_{3}^{⊝}$ and CO₂or ${CO}_{3}^{2 -}$ depending on the acidity of the reaction mixture.
${CN}^{⊖} ⟶ {CO}_{2} + {NO}_{3}^{⊖} + H^{\oplus} + {ne}^{-}$
The number of (n) of electron involved in the process divided by 10 is

Moderate

Solution

After balancing the equation.
$15 H_{2} O + 3 {CN}^{Θ} \to 3 {CO}_{2} + 3 {NO}_{3}^{θ} + 30 H^{\oplus} + 30 e^{-}$
$∴ Number of electrons = \frac{30}{10} = 3$

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