First slide

Diborane

Question

A compound X, of boron reacts with NH₃ on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF₃ with lithium aluminium hydride. The compounds X and Y are represented by the formulas

Difficult

A

B₂H₆, B₃N₃H₆
B

B₂O₃, B₃N₃H₆
C

BF₃, B₃N₃H₆
D

B₃N₃H₆, B₂H₆

Solution

Reaction of Diborane with NH₃:
Case-I
Case-II
${B_2}{H_6} + \mathop {N{H_3}}\limits_{Excess} \xrightarrow{{High\,\,temperature}}\mathop {{{\left( {BN} \right)}_n}}\limits_{Boron\,\,nitride}$
Case-III
$\mathop {3{B_2}{H_6} + 6N{H_3}}\limits_{\boxed{1\,\,\,\,\,\,\,\,\,\,\,\,\,:\,\,\,\,\,\,\,\,\,\,\,2}} \xrightarrow{{High\,\,temperature}}\mathop {{{\left( {BN} \right)}_n}}\limits_{Boron\,\,nitride}$
$4B{F_3} + 3LiAl{H_4}\xrightarrow{{Diethyl\,\,ether}}\mathop {2{B_2}{H_6}}\limits_X + 3LiF + 3Al{F_3}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App