First slide

13th group or boron group

Question

The compounds of type $E C l_{3}$ where E=B,P,As(or) Bi the angles $C l - E - C l$ for different E are in the order.

Moderate

A

$B > P = A s = B i$
B

$B > P > A s > B i$
C

$B < P = A s = B i$
D

$B < P < A s < B i$

Solution

1) In $B C l_{3}$ , Boron undergoes $s p^{2}$ Hybridization. So the bond angle is $120^{\circ} C$
2) In $P C l_{3}, A s C l_{3,} B i C l_{3}$ , & the central atom undergoes $s p^{3}$ and one lone pair. Hence the bond angles< $109^{\circ} 28^{'}$
3) When the hybridization and the number of lone pairs are same, then as the size of the central atom increases, bond angle decreases.

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