Correct statement(s) among (I) to (IV) regarding group 14 elements is (are)I) Silicon exists in diamond form and does not have an allotrope which resembles graphite.II) All elements other than carbon in this group can expand their octet.III) Hybridization of Sn in [Sn(OH)6 ]2− is sp3d2.IV) Lead does not from any tetrahalides while all other elements of the group form.
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a
I, II, III, IV
b
I, II, III only
c
I, II only
d
II, III, IV only
answer is B.
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Detailed Solution
I) Correct. As silicon cannot for pi bond involving p-orbitals, it does not have a graphite analogue.II) Correct. They all have empty d-orbitals to expand their octet.III) Correct.IV) Lead forms tetrahalides except iodide.
Correct statement(s) among (I) to (IV) regarding group 14 elements is (are)I) Silicon exists in diamond form and does not have an allotrope which resembles graphite.II) All elements other than carbon in this group can expand their octet.III) Hybridization of Sn in [Sn(OH)6 ]2− is sp3d2.IV) Lead does not from any tetrahalides while all other elements of the group form.