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The d-electron configuration of $[Ru {(en)}_{3}] {Cl}_{2}$ and $[Fe {(H_{2} O)}_{6}] {Cl}_{2}$ respectively are:

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t2g4 eg2 and t2g6 eg0

t2g6 eg0 and t2g4 eg2

t2g4 eg2 and t2g4 eg2

t2g6 eg0 and t2g6 eg0

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detailed solution

Correct option is B

Fe and Ru belong to same group and their ions Fe2+ and Ru2+ in the given complex have d6 configuration. In Ruen3Cl2, the electrons rearrange having t2g6eg0. In FeH2O62+since H2O is weak k ligand electrons do not rearrange. So have t2g4eg2.

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The d-electron configuration of [Ru(en)3]Cl2 and [Fe(H2O)6] Cl2 respectively are:

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The d-electron configuration of $[Ru {(en)}_{3}] {Cl}_{2}$ and $[Fe {(H_{2} O)}_{6}] {Cl}_{2}$ respectively are: