The d-electron configuration of [Ru(en)3]Cl2 and [Fe(H2O)6] Cl2 respectively are:
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a
t2g4 eg2 and t2g6 eg0
b
t2g6 eg0 and t2g4 eg2
c
t2g4 eg2 and t2g4 eg2
d
t2g6 eg0 and t2g6 eg0
answer is B.
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Detailed Solution
Fe and Ru belong to same group and their ions Fe2+ and Ru2+ in the given complex have d6 configuration. In Ruen3Cl2, the electrons rearrange having t2g6eg0. In FeH2O62+since H2O is weak k ligand electrons do not rearrange. So have t2g4eg2.