First slide

Water and Heavy water

Question

Deutero methane is obtained by the deuterolysis of

Easy

A

Mg₃N₂
B

CaC₂
C

Al₄C₃
D

Ca₃P₂

Solution

The addition of deuterated water (D₂O) in the form of D⁺ $OD^\circleddash$ to a compound is called Deuterolysis

Mg₃N₂ + 6H₂O→ 3Mg(OD)₂ + 2ND₃ (Deuterated ammonia)
$\large M{g_3}{N_2}\; \Rightarrow \;\begin{array}{{20}{c}} {3M{g^{ + 2}}}&{2{N^{ - 3}}} \\ {6O\mathop D\limits^ - }&{6{H^ + }} \end{array}$

CaC₂ + 2D₂O → Ca(OD)₂ + C₂O₂ (Deuterated acetycene)
$\large C{a_2}C\; \Rightarrow \;\begin{array}{{20}{c}} {C{a^{ + 2}}}&{{C_2}^{ - 3}} \\ {6O\mathop D\limits^ - }&{6{D^ + }} \end{array}$

Al₄C₃ + 12D₂O→ 4Al[OD]₃ + 3CD₄(Deuteromethane)
$\large A{l_4}{C_3}\; \Rightarrow \;\begin{array}{{20}{c}} {4A{l^{ + 3}}}&{3{C^{ - 4}}} \\ {6O\mathop D\limits^ - }&{12{D^ + }} \end{array}$

Ca₃P₂ + 6D₂O → 3Ca(OD)₂ + 2PD₃ (DeuteroPhosphene)
$\large C{a_3}{P_2}\; \Rightarrow \;\begin{array}{{20}{c}} {3C{a^{ + 3}}}&{2{P^{ - 3}}} \\ {6O\mathop D\limits^ - }&{6{H^ + }} \end{array}$

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