The equation which is balanced and represents the correct product(s) is
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a
Li2O+2KCl→2LiCl+K2O
b
CoClNH35+5H+→Co2++5NH4++Cl−
c
MgH2O62++EDTA4−→excess NaOHMgEDTA2++6H2O
d
CuSO4+4KCN→K2CuCN4+K2SO4
answer is B.
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Detailed Solution
(a) Li2O+2KCl→2LiCl+K2OThe above equation is incorrect because amine a stronger base cannot be generated by a weaker base, Li2O(b) CoClNH35++5H+→Co2++5NH4++Cl−The above equation is correct because amine complexes decompose under acidic medium. Thus, the complex [CoCl(NH3)5] decomposes under acidic conditions to give ammonium ions.(c) MgH2O62++EDTA4−→excess NaOHMgEDTA2++6H2OThe above equation is incorrect because the product formed would be [Mg (EDTA)]2-.(d) CuSO4+4KCN→K2CuCN4+K2SO4The above equation is incorrect. Thus, the correct equation is2KCN+CuSO4→K2SO4+Cu+CN2Cyanogen gas