First slide

Applications of complexes

Question

The equation which is balanced and represents the correct product(s) is

Easy

A

${Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O$
B

$[CoCl {({NH}_{3})}_{5}] + 5 H^{+} \to {Co}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$
C

${[Mg {(H_{2} O)}_{6}]}^{2 +} + {(EDTA)}^{4 -} \overset{excess NaOH}{\to} [Mg {(EDTA)}^{2 +} + 6 H_{2} O]$
D

${CuSO}_{4} + 4 KCN \to K_{2} [Cu {(CN)}_{4}] + K_{2} {SO}_{4}$

Solution

(a) ${Li}_{2} O + 2 KCl \to 2 LiCl + K_{2} O$
The above equation is incorrect because amine a stronger base cannot be generated by a weaker base, ${Li}_{2} O$
(b) ${[CoCl {({NH}_{3})}_{5}]}^{+} + 5 H^{+} \to {Co}^{2 +} + 5 {NH}_{4}^{+} + {Cl}^{-}$
The above equation is correct because amine complexes decompose under acidic medium. Thus, the complex [CoCl(NH₃)₅] decomposes under acidic conditions to give ammonium ions.
(c) ${[Mg {(H_{2} O)}_{6}]}^{2 +} + {(EDTA)}^{4 -} \overset{excess NaOH}{\to} [Mg {(EDTA)}^{2 +} + 6 H_{2} O]$
The above equation is incorrect because the product formed would be [Mg (EDTA)]^2-.
(d) ${CuSO}_{4} + 4 KCN \to K_{2} [Cu {(CN)}_{4} + K_{2} {SO}_{4}]$
The above equation is incorrect. Thus, the correct equation is
$2 KCN + {CuSO}_{4} \to K_{2} {SO}_{4} + Cu + \underset{(Cyanogen gas)}{{(CN)}_{2}}$

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