First slide

Hydrogen Peroxide

Question

Excess of ozone when passed through 1 lit of 1M H₂O₂ solution, the volume of oxygen liberated at STP will be.......

Easy

A

11.2 lit
B

22.4 lit
C

5.6 lit
D

44.8 lit

Solution

$\large \mathop {{H_2}{O_2}}\limits_{1mole} + {\rm{ }}{O_3}\;{\rm{ }} \to {\rm{ }}{H_2}O\; + \;\mathop {2{O_2}}\limits_{2mole}$
$\large \\\\M =\frac{\eta }{V lit}\\\\\eta\;=\;M\times\;V(lit)\\\\\eta\;=\;1\times 1\\\\\eta\;=\;1mole$
1 mole --------------------2 x 22.4
= 44.8 lit
$\large \therefore$ volume of O₂ liberated at STP when excen of O₃ is passed though 1lit of 1M H₂O₂ solution is 44.8 lit.

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