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A hydrogen atom in its ground state is irradiated by light of wavelength 970 Ao. Taking hc/e = 1.237 × 10-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is

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answer is 6.

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Detailed Solution

Absorbed quantum energy in (eV) =hceλ=1.237×10−6970×10−10= 12.75 eVEnergy of nth shell =-13.6 + 12.75= -0.85 eVWe know,En=E1n2∴n2=E1En=−13.6−0.85=16i.e., n = 4.Number of spectral emission lines =nn−12=4×32=6
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