lf the ionisation energy of Na is 495.8 kJ mol-1, the electron affinity of Cl is 349.4 kJ mol-1 and lattice energy is 776 kJ mol-1, the true statement for the formation of ionic bondin NaCI is

Na(g)+495.8⟶Na+(g)+e−            . . . (i) Cl(g)+e−⟶Cl−(g)+349.4 Na+(g)+Cl−(g)⟶NaCl(s)+776 kJ mol−1Total energy released per mole of NaCl formed = 776 + 349.4 = 1125.4 kJTotal energy absorbed in step (i) = 495.8 kJNet energy released = 629.6 kJThus, a stable ionic bond is formed between NaCl.