Chemical Equilibrium

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Question

The pressure at which equilibrium constant in term of pressure is found to be equal to that in terms of mole fraction for the equilibrium,
${PCl}_{5 (g)} ⇌ {PCl}_{3 (g)} + {Cl}_{2 (g)} is :$

Moderate

Solution

$\begin{aligned} K_{P} = K_{x} (P)^{{Δn}_{g}} \\ ∴ K_{P} = K_{x} (P) \end{aligned}$
$Thus, K_{p} = K_{x}, when P = 1 atm$

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