First slide

Chemical Equilibrium

Question

Pure gas –A was taken in a closed container at an initial pressure of 5atm the pressure in the container changed due to the reactions
$\underset{(g)}{A} ⇌ \underset{(g)}{B} + 2 \underset{(g)}{C}$
$\underset{(g)}{C} ⇌ \underset{(g)}{B} + \underset{(g)}{D}$
If the total pressure due to the mixture of gases A, B,C and D was found to be 10atm at equilibrium in which pressure due to C was 3 atm then kp for the first equilibrium is

Moderate

Solution

$\underset{5 - x}{A} ⇌ \underset{(x + y)}{B} + \underset{(2 x - y)}{2 C}$
$\underset{(2 x - y)}{C} ⇌ \underset{(y + x)}{B} + \underset{(y)}{D}$
$P_{A} + P_{B} + P_{C} + P_{D} = (5 - x) + (x + y) + (2 x - y) + y = 2 x + y + 5 = 10$
$\Rightarrow 2 x + y = 5 - - - 1$
$P_{C} = 2 x - y = 3 . . . . 2$
From 1 and 2 , x = 2
$\Rightarrow y = 1$
$P_{A} = 5 - 2 = 3$
$P_{B} = 3 P_{C} = 3$
$K_{p} = \frac{3^{2} \times 3}{3} = 9$

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