For the reaction, A+B⇌C+Dthe initial concentration of A and B are equal, but the equilibrium concentration of C is twice that of equilibrium concentration of A. The equilibrium constant is:
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answer is 4.
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Detailed Solution
A B ⇌ C D a a 0 0 (1-α) (1-α) α α Kc=[C][D][A][B]=2(1-α).2(1-α)(1-α)(1-α)=4
For the reaction, A+B⇌C+Dthe initial concentration of A and B are equal, but the equilibrium concentration of C is twice that of equilibrium concentration of A. The equilibrium constant is: