The reaction of $$H3$$ $$N3$$ $$B3Cl3($$ $$A)$$ with $$LiBH4$$ in THF gives a $$compound(B)$$.Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively $$___$$?

Question

The reaction of $$H3$$ $$N3$$ $$B3Cl3($$ $$A)$$ with $$LiBH4$$  in THF gives a $$compound(B)$$.Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively $$___$$?

Infinity Learn · Accepted Answer

When $$H3$$ $$B3$$ $$N3Cl3$$ reacts with $$LiBH4$$ gives Borazine  $$H3$$ $$N3$$ $$B3Cl3+3LiBH4$$⟶$$THFH3$$ $$N3$$ $$B3H3$$             (A)                         (B)   $$H3$$ $$N3$$ $$B3Cl3+3CH3MgBr$$→$$H3$$ $$N3$$ $$B3CH33+3MgBrCl$$       (A)                                      (C)                 (D)

The reaction of $H_{3} N_{3} B_{3} {Cl}_{3} (A) with {LiBH}_{4}$ in THF gives a compound(B).Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively ___?

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The reaction of H3 N3 B3Cl3( A) with LiBH4 in THF gives a compound(B).Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively ___?

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The reaction of $H_{3} N_{3} B_{3} {Cl}_{3} (A) with {LiBH}_{4}$ in THF gives a compound(B).Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively ___?