The reaction of H3 N3 B3Cl3( A) with LiBH4  in THF gives a compound(B).Further the reaction of (A) with three moles of methylmagnesium Bromide gives the compound C and D. Then the compounds B and C are respectively ___?

When H3 B3 N3Cl3 reacts with LiBH4 gives Borazine  H3 N3 B3Cl3+3LiBH4⟶THFH3 N3 B3H3             (A)                         (B)   H3 N3 B3Cl3+3CH3MgBr→H3 N3 B3CH33+3MgBrCl       (A)                                      (C)                 (D)