Questions
A solution containing 2.615 g of CoCl3 6NH3 (molar mass = 267 g mol-1) is passed through a cation exchanger' The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl. The formula of the complex is:
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Correct option is A
No. of moles of complex =2.675267.5=0.01No. of moles of AgCI =4.78143.5=0.03This shows that three Cl- ions are precipitated.Thus, formula of the complex is CoNH36Cl3.Similar Questions
According to werner primary valency of central atom in Complex is
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