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Q.

A solution containing 2.615 g of CoCl3 6NH3 (molar mass = 267 g mol-1) is passed through a cation exchanger' The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl. The formula of the complex is:

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a

CoNH36Cl3

b

CoNH33Cl33NH3

c

CoNH34Cl2Cl2NH3

d

CoNH35ClCl2NH3

answer is A.

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Detailed Solution

No. of moles of complex =2.675267.5=0.01No. of moles of AgCI =4.78143.5=0.03This shows that three Cl- ions are precipitated.Thus, formula of the complex is CoNH36Cl3.
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