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Q.

A solution containing 2.675 grams of CoCl3 . 6NH3 (molar mass = 267.6 gr . mole−1) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 grams of AgCl (Molar mass=  143.5 gr mole−1). The formula of the complex is

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a

CoNH36Cl3

b

CoCl2NH34Cl

c

CoCl3NH33

d

CoClNH35Cl2

answer is A.

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Detailed Solution

WAgCl  precipitated=4.78gnAgCl  precipitated=4.78143.5=0.0333Wcomplex=2.675 gncomplex = 2.675267.5=0.010.01 moles of complex gave 0.033 moles of AgCl1 mole of complex gives 3 moles of AgClso one mole complex must have three moles of ionizable chloride ions.The complex is [Co(NH3)6]Cl3 .
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