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Hydrogen Peroxide

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By Expert Faculty of Sri Chaitanya

Question

In transforming 0.01mole of PbS to PbSO₄ the volume of ‘10volume’ H₂O₂ required will be

Moderate

Solution

PbS + 4H2O2 → PbSO4 + 4H2O
1 mole - 4 mole
0.01 mole - ??
$\frac{0.01 \times 4}{1} = 0.04 moles of H_{2} O_{2}$
$n = \frac{weight}{Molecular weight} Weight = 0.04 \times 34 = 1.36 gr 34 gr of H_{2} O_{2} solution contains = 1.36 gr of H_{2} O_{2} 10 vol of H_{2} O_{2} (3.03 gr) \to 100 ml 1.36 gr \to ? ? \frac{1.36 \times 100}{3.03} = 44.8 ml$

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