In transforming 0.01mole of PbS to PbSO4 the volume of ‘10volume’ H2O2 required will be

PbS + 4H2O2 → PbSO4 + 4H2O1 mole - 4 mole0.01 mole - ?? n=weightMolecular weight Weight=0.04×34=1.36 gr 34 gr of H2O2 solution contains=1.36 gr of H2O2 10 vol of H2O2(3.03 gr)→100 ml                            1.36 gr →?? 1.36×1003.03=44.8 ml