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The weight of iron which will be converted into its oxide (Fe3O4 ) by the action of 18 g of steam on it will be (Atomic weight of Fe = 56)

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By Expert Faculty of Sri Chaitanya
a
168 g
b
84 g
c
42 g
d
21 g

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detailed solution

Correct option is C

3Fe + 4H2O   → Fe3O4+4H23×56g   4× 18 g= 168 g     = 72 g∵ 72 g steam required Fe = 168 g ∴ 18 g steam required Fe = 168×1872 = 42 g


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