First slide

Alkenes

Question

In which of the following molecule all carbon atoms are in one plane.

Moderate

A

butane
B

1-butene
C

1,2-butadiene
D

1,3-butadiene

Solution

[Step 1]:
In option (1) butane ${CH}_{3} - {CH}_{2} - {CH}_{2} - {CH}_{3}$ all four carbon atoms are SP³ hybridised and arranged tetrahedrally.
[Step 2]:
In option (2) 1-butene ${CH}_{2} = CH - {CH}_{2} - {CH}_{3}$ two carbons are SP² and planar arrangement other two carbons are SP³ and tetrahedral arrangement.
[Step 3]:
In option (3) 1,2-butadiene ${CH}_{2} = C = CH - {CH}_{3}$ three carbons are SP² and planar arrangement. One carbons are SP² and tetrahedral.
[Step 4]: (4) 1,3-butadiene ${CH}_{2} = CH - CH = {CH}_{2}$ all four carbons are SP² and planar arrangement.

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