First slide

Group 14 or carbon family

Question

Which of the following is non- reducing?

Easy

A

$P b O_{2}$
B

$S n O$
C

$S b_{2} O_{3}$
D

$I n_{2} O$

Solution

In the 13th, 14th and 15th group stability of lower oxidation state increases down the group. This phenomenon is termed as inert pair effect.
$s t a b i l i t y : P b^{+ 2} > P b^{+ 4}$
Therefore, $P b O_{2}$ is a strong oxidizing agent.

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