First slide

Crystal field theory

Question

Which one of the following is outer orbital complex

Easy

A

${[Co {({NH}_{3})}_{6}]}^{+ 3}$
B

${[Mn {(CN)}_{6}]}^{-3}$
C

${[Fe {(CN)}_{6}]}^{4 -}$
D

${[Ni {({NH}_{3})}_{6}]}^{+ 2}$

Solution

The hybridization of metal ion in octahedral complexes will be sp³d² (or) d²dp³.
In the ions with configuration d⁸,d⁹,d¹⁰there is no availability of two vacant d-orbitals in (n-1) d substance.
Moreover they cannot rearrange. Thus for the octahedral complexes having the metal ions with d⁸, d⁹, d¹⁰ configuration the hybridization is always sp³d². They form outer orbital complexes without undergoing rearrangement.

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