Questions
In a circus there are ten cages for accommodating ten animals. Out of these four cages are so small that five out of 10 animals cannot enter into them. In how many ways will it be possible to accommodate ten animals in these ten cages?
detailed solution
Correct option is B
At first we have to a accommodate those 5 animals in cages which cannot enter in 4 small cages, thereforenumber of ways are 6P5 and rest of the five animals arrange in 5! ways.Total number of ways =5!×6P5=120×720=86400Similar Questions
The total number of 5-digit numbers of different digits in which the digit in the middle is the largest is
799 666 8865
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