Questions
Given 5 different green dyes, 4 different blue dyes and 3 different red dyes, the number of combinations of dyes that can be chosen by taking at least one green and one blue dye is
detailed solution
Correct option is C
Number of ways of selecting at least one green dye out of 5 different green dyes 5C1+5C2+5C3+5C4+5C5=25−1Also, at least one blue dye can be selected out of 4 blue dyes in 4C1+4C2+4C3+4C4=24−1Again, 3 different red dyes can be selected in 3C0+3C1+3C2+3C3=23 ways∴ Required ways =25−124−123=3720Similar Questions
Let be a set containing elements. The number of reflexive relations that can be defined on is
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