Questions
If is the area of the triangle formed by the centroid and two vertices of a triangle, is the area of the triangle formed by the mid-points of the sides of the same triangle, then
detailed solution
Correct option is C
Let Ax1,y1,Bx2,y2 and Cx3,y3 be the vertices of a ∆ ABC, and let G be its centroid. Then,Δ1= Area of ΔGBC⇒Δ1=12x1+x2+x33y1+y2+y331x2y21x3y31⇒Δ1=16x1+x2+x3y1+y2+y33x2y21x3y31 Applying R1→R1(3)⇒Δ1=16x1 y1 1x2 y2 1x3 y3 1 Applying R1→R1−R2−R3⇒Δ1=Δ3 where ∆is the area of ∆ABCΔ2=Area of triangle formed by the mid-points of the sides⇒Δ2=x1+x22y1+y221x2+x32y2+y321x3+x12y3+y1211⇒Δ2=18x1+x2y1+y21x2+x3y2+y31x3+x1y3+y11 Applying C1→C1(2),C2→C2(2)⇒Δ2=182x1+x2+x32y1+y2+y33x2+x3y2+y31x3+x1y3+y11 Applying R1→R1+R2+R3⇒Δ2=28x1+x2+x3y1+y2+y332x2+x3y2+y31x3+x1y3+y11 Applying R1→R1(1/2)⇒Δ2=14x1+x2+x3y1+y2+y33/2−x1−1/1−1/2−x2−1/2−1/2 R2→R2−R1R3→R3−R1⇒ Δ2=18x1+x2+x3y1+y2+y33−x1−y1−1−x2−y2−1 Applying C3→C3⇒ Δ2=18x3 y3 1−x1 −y1 −1−x2 −y2 −1 Applying R1→R1+R2+R3⇒ Δ2=14Δ∴ Δ1:Δ2=4:3Talk to our academic expert!
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Consider a point where m and n are positive integers.B is the reflection of A in the line is the reflection of B in the y-axis, D is the reflection of C in the x-axis and E is the reflection of D in the y-axis. The area of the pentagon is
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