If the centroid of an equilateral triangle . (2, - 2) and its one vertex is (-1, 1), then the equation ofcircumcircle is
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a
x2+y2−4x+4y−10=0
b
x2+y2+4x−4y+10=
c
x2+y2+4x−4y−10=0
d
x2+y2−4x+4y+10=
answer is A.
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Detailed Solution
Circumcircle of the equilateral triangle hascentre at(2, - 2) and passes through(-1, 1). So, its equation is(x−2)2+(y+2)2=(2+1)2+(−2−1)2⇒x2+y2−4x+4y−10=0