If sum of the elements in the range of f(x)=sin−1x+cos−1x+tan−1x+tan−11x+sec−1x+cosec−1x is kπ, then k=
3
0
1
2
We know that (1) sin−1x+cos−1x=π2;∀x∈[−1,1]
(2) tan−1x+tan−11x=π2 if x≥0−π2 if x<0
(3) sec−1(x)+cosec−1(x)=π2;∀x∈(−∞,−1]∪[1,∞)
Only -1 and 1 satisfies the given equation
f(−1)=π2+−π2+π2=π2f(1)=π2+π2+π2=3π2∴ Range is π2,3π2
Sum of the elements in the range is 2π⇒k=2
Therefore, the correct answer is (4).