First slide
Relations XII
Question

Let S be the set of all subsets of first 10 natural numbers. If a relation R is defined on set S such that (A, B) R if    ABϕ;where  A,BS, then R is 

Moderate
Solution

ϕϕ=ϕ(ϕ,ϕ)R

R is not reflexive 

Clearly R is symmetric but not transitive      (  if A ={1,2,3}  ,  B={ 3, 4 }  , C = {4,5,6} then     AB ={3}     and  B C    but  A C  = .      so not transitive )

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