First slide
Definition of a circle
Question

A line is drawn through a fixed point P (α, β) to cut the circle  

x2+y2=r2  at A and  B .Then PAPB is equal to 

Moderate
Solution

The equation of any line throughP (α, β) is 

xαcosθ=yβsinθ=k(say)

Any point on this line is  (α+ k cos θ, β + k sinθ). This point lies on the given circle if

(α+kcosθ)2+(β+ksinθ)2=r2

k2+2k(αcosθ+βsinθ)+α2+β2r2=0             (i)

This equation, being quadratic in k, gives two values of k and hence the distances of two points A and B on the circle from the point P. 

Let PA=k1,PB=k2, where k1,k2 are the roots of equation (i)

Then, 

 PAPB =k1k2=α2+β2r2

ALITER  PAPB is the power of the point P(α,β) ) with respect to the circle x2+y2=r2 . Therefore , 

PAPB=α2+β2r2 

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