Questions
A person throws a dice while he gets a number greater than 2. The probability that he gets a 6 in the last throw is
detailed solution
Correct option is D
Let E1, be the event that six shows when a dice is thrown. Let E2 be the event that number less than or equal to 2 shows when a dice is thrown.PE1=1/6 and PE2=2/6=1/3E = the event that six turns up in the last throw = the event that E1 happens in the all previous throws and E2 happens in the last throw P(E)=PE1E2 or E1E1E2 or E1E1E1E2…..=PE1⋅PE2+PE1⋅PE1⋅PE2+PE1⋅PE1⋅PE1⋅PE2+…=13⋅16+132⋅16+133⋅16+…P(E)=13⋅16×11−1/3⇒P(E)=112Similar Questions
The odd against an event are 5 to 2 and the odds in favour of another disjoint event are 3 to 5. Then the probability that atleast one of the events will happen is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests