A person throws a dice while he gets a number greater than 2. The probability that he gets a 6 in the last throw is

Let E1, be the event that six shows when a dice is thrown. Let E2 be the event that number less than or equal to 2 shows when a dice is thrown.PE1=1/6 and PE2=2/6=1/3E = the event that six turns up in the last throw = the event that E1 happens in the all previous throws and E2 happens in the last throw P(E)=PE1E2 or E1E1E2 or E1E1E1E2…..=PE1⋅PE2+PE1⋅PE1⋅PE2+PE1⋅PE1⋅PE1⋅PE2+…=13⋅16+132⋅16+133⋅16+…P(E)=13⋅16×11−1/3⇒P(E)=112