Which of the following is always true?
(~p∨~q)≡(p∧q)
(p→q)≡(~q→∼p)
~(p→∼q)≡(p∧~q)
~(p↔q)≡(p→q)→(q→p)
Since, ~(p∨q)≡(~p∧~q) and ~(p∧q)≡(~p∨q)
So,. option (b) and (d) are not true.
(p→q)≡p∧~q so option (c) is not true.
p→q~p∨q~q→∼p≡[~(~q)∨~p]≡q∨~p≡∼p∨q p→q≡∼q→∼p