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Which of the following is always true?
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a
(~p∨~q)≡(p∧q)
b
(p→q)≡(~q→∼p)
c
~(p→∼q)≡(p∧~q)
d
~(p↔q)≡(p→q)→(q→p)
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Correct option is B
Since, ~(p∨q)≡(~p∧~q) and ~(p∧q)≡(~p∨q)So,. option (b) and (d) are not true.(p→q)≡p∧~q so option (c) is not true. p→q~p∨q~q→∼p≡[~(~q)∨~p]≡q∨~p≡∼p∨q p→q≡∼q→∼p
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