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In which of the following function is rolle’s theorem applicable?

a
f(x)={x,         0≤x≤10,         x=1  on[0,1]
b
f(x)={sinxx,         −π≤x≤o0,                    x=0  on[−π,0]
c
f(x)=x2−x−6x−1on[−2.3]
d
f(x)={x3−2x2−5x+6x−1,  if x≠1, −6,                                 if  x=1

detailed solution

Correct option is D

A) Discontinuous at x=1 ⇒ not applicable. B) F(x)  is not continuous (jump discontinuity) at x=0.C) Discontinuity (missing point) at x=1 ⇒  not applicable.D) notice that x3−2x2−5x+6=(x−1)(x2−x−6). hence, f(x)=x2−x−6 if x≠1 and f(1)=−6. ⇒f  is continuous at x=1. So f(x)=x2−x−6  throughout the interval [−2,3]. Also, note that f(−2)=f(3)=0.  hence, Rolle’s theorem applies. f'(x)=2x−1. Setting f'(x)=0,  we obtain x= 12  which lies between –2 and 3.

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