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An αparticle and a proton are both simultaneously projected in opposite directions into a region of constant magnetic field perpendicular to the direction of the field. After some time it is found that the velocity of the αparticle has changed in direction by 45°. Then at this time, the angle between velocity vectors of αparticle and proton is

a
90°
b
45°
c
135°
d
none

detailed solution

Correct option is C

ω=qB/m,  ωP =  eB/m,  ωα =  2eB4m=  ωP/2So proton will cover double angle in same time as that of α−particle Clearly from figure angle between vα  and vP is  1350.

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