An α−particle and a proton are both simultaneously projected in opposite directions into a region of constant magnetic field perpendicular to the direction of the field. After some time it is found that the velocity of the α−particle has changed in direction by 45°. Then at this time, the angle between velocity vectors of α−particle and proton is
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a
90°
b
45°
c
135°
d
none
answer is C.
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Detailed Solution
ω=qB/m, ωP = eB/m, ωα = 2eB4m= ωP/2So proton will cover double angle in same time as that of α−particle Clearly from figure angle between vα and vP is 1350.