Questions
In an adiabatic change, the pressure and temperature of a monoatomic gas are related with relation as P , where C is equal to
a
54
b
53
c
35
d
52
detailed solution
Correct option is D
For adiabatic process,PVγ = constant----------------(i)We have ideal gas relation, PV = RT⇒ V = RTP-----------------(ii)From Eqs. (i) and (ii), we get P(RTP)γ =constant ⇒ TγPγ-1 = constant-------------(iii)where γ is adiabatic constant of the gas.Given, P ∝ TCOn comparing with Eq. (iii), we have,C = γγ-1For a monoatomic gas γ = 53∴ We have, C = 5353-1= 52Talk to our academic expert!
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