First slide
Law of equipartition of energy
Question

The average degrees of freedom per molecule of a gas are 6. The gas performs 25J of work when expands at constant pressure. The heat absorbed by the gas is 

Moderate
Solution

according to equipartition law of energy CV=f2R = 3R  then CP=4R and γ for the gas will be 43 at constant pressure process 1-1γ part of total heat is used for work done then 1/4 th of the total heat is work done =25 J  hence total heat absobed will be 100 J

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