The average translational kinetic energy of oxygen molecules is 0.05 eV. Calculate the temperature of the oxygen. Use 1eV=1.6×10–19J.Boltzmann’s constant, k=1.38×10–23J K–1 .
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
300 K
b
386 K
c
420 K
d
475 K
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The average translational kinetic energy of a molecule, KEavg=32kT⇒0.05×1.6×10–19=32kTOr, T = 386 K.