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The average translational kinetic energy of oxygen molecules is 0.05 eV. Calculate  the temperature of the oxygen. Use 1eV=1.6×1019J.Boltzmann’s constant,  k=1.38×1023J K1 .

a
300 K
b
386 K
c
420 K
d
475 K

detailed solution

Correct option is B

The average translational kinetic energy of a molecule, KEavg=32kT⇒0.05×1.6×10–19=32kTOr, T = 386 K.

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