A ball of thermal capacity $$10$$ cal $$/o$$ C is heated to the temperature of furnace. It is then transferred into a vessel containing water. The water equivalent of vessel and the contents is $$200$$ gm. The temperature of the vessel and its contents rises from $$10oC$$ to $$40oC$$. What is the temperature of furnace ?

Question

Infinity Learn · Accepted Answer

Thermal capacity of ball $$=$$ mc $$=$$ $$10$$ cal $$/o$$ CLet T be the furnace temperature.Water eq. of vessel and contents $$=$$ mc $$=$$ $$200$$ gm.Resultant temperature $$=$$ $$40oCAccording$$ to principle of calorimetry,Heat lost by hot body $$=$$ heat gained by cold $$bodymc(T$$−$$40)=mc(40$$−$$10)10(T$$−$$40)=200$$×$$30$$∴$$T=640$$∘C.

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