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Balmer gives an equation for wavelength of visible radiation of H-spectrum as  λ=kn2n24. The value of k in terms of Rydberg’s constant R is 

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a
R
b
4R
c
R/4
d
4/R

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detailed solution

Correct option is D

1λ  =  R Z21n12 −  1n22.  For  H−atom  Z=1.For visible radiation, n1=2∴    1λ  =  R 12 2 −  1n 2 ⇒  λ=4n2Rn2−4=k  n2n2−4  ⇒  k=4R.


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