A body of mass m is projected horizontally with a velocity v from the top of a tower of height h and it reaches the ground at a distance x from the foot of the tower. If a second body of mass $$2m$$ is projected horizontally from the top of a tower of height $$2h$$, it reaches the ground at a distance $$2x$$ from the foot of the tower. The horizontal velocity of the second body is:

Question

Infinity Learn · Accepted Answer

For the first body, h $$=$$ $$12gt2----------(i)and$$ x $$=$$ vt $$-----------(ii)From$$ equation (i) and (ii)h$$ $$=$$ $$12g$$.$$(x2v2)-------(iii)2h=12g$$.$$(4x2v$$'$$2)-------(iv)Dividing$$ equation $$(iii) by equation (iv) we $$get12=$$ $$x2v2$$×v'$$24x2$$ or v' $$=$$ $$2v$$

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