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In Bohr’s theory the potential energy of an electron at a position is $\frac{K r^{2}}{2}$ (where $K$ is a positive constant); then the quantized energy of the electron in nth orbit is:

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Correct option is B

GivenPotential energy of an electron U=Kr22Where K=Positive constantWe use force on electron F=dUdr=Kr=mv2r∵Fc=mv2r⇒mv2=Kr2 and mvr=nh2πmrKmr=nh2π ⇒r=nh2πKmEnergy of nth orbit is En=Kr22+Kr22=Kr2⇒En=Knh2πKm=nh2πKm

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In Bohr’s theory the potential energy of an electron at a position is Kr22 (where K is a positive constant); then the quantized energy of the electron in nth orbit is:

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In Bohr’s theory the potential energy of an electron at a position is $\frac{K r^{2}}{2}$ (where $K$ is a positive constant); then the quantized energy of the electron in nth orbit is: