Questions
A box of 100 kg is sliding down along a rough inclined plane of height 2m and length 4m. If coefficient of friction is 0.5 then the force required to be applied so that it comes down with a constant velocity is
detailed solution
Correct option is D
The force required to make it fall with a constant velocity is the same as the force due to which it is coming down but in opposite direction. i:e.mgsinθ-μmgcosθ= mgsinθ-μcosθ here sinθ=24=0.5 θ =300100×100.5-0.532=500×0.134=67Talk to our academic expert!
Similar Questions
A box is lying on an inclined plane what is the coefficient of static friction if the box starts sliding
when an angle of inclination is 60° ?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests