First slide

First law of thermodynamics

Question

540 calories of heat convert l cc of water at 100°C to 1671 cc of steam at 100°C under atmospheric conditions. Increase in internal energy will be nearly:

Easy

A

300 calorie
B

20 calorie
C

500 calorie
D

540 calorie

Solution

$∆ U = Q - W = 540 - P ∆ V = 540 - \frac{10^{5} \times 1670 \times 10^{- 6}}{4.2} = 540 - 40 = 500 cal$

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