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Carbon monoxide is carried around a closed cycle abc in which bc is an isothermal process as shown in the figure. The gas absorbs 7000J of heat as its temperature 300k to 1000k in going from a to b. The quantity of heat rejected by the gas during the process ca is

a
4200J
b
5000J
c
9000J
d
9800J

detailed solution

Correct option is D

For path  ab:ΔUab=7000JBy using  ΔU=nCvΔT 7000=n×52R×700n = 0.48For path  ca:ΔQca=ΔUca+ΔWca−−−−1 ∵(ΔU)ab+(ΔU)bc+(ΔU)ca=0∴7000+0+(ΔU)ca=0(ΔU)ca=−7000J−−−−(2) Also  ΔWca=P1V1−V2=nRT1−T2= -2792.16 J--------(3)Solving (1), (2) and (3)ΔQca=−7000−2792.16 =-9792.16J=-9800J

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