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A carnot engine whose source is at 400 K takes 200 cal of heat and rejects 150 cal to sink. What is the temperature of sink?

a
800 K
b
400 K
c
300 K
d
200 K

detailed solution

Correct option is C

In carnot engine  source temperature T1=400 K (given)  amount of heat given is Q1=200 cal  amount of heat rejected Q2=150 cal  temperature of sink is T2=?  work done by engine is W=Q1-Q2 =200-150=50cal  substitute given values,  ⇒W=50 cal  efficiency is η=WQ1  substitute values legibly  η=50200=14  another equation for efficiency in terms of temperature isη=1-T2T1  substitute η value 1/4 in above eqn14=1−T2400 ⇒T2400=1−14=34 ⇒T2=300 K=temperature of sink

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