First slide

Force on a charged particle moving in a magnetic field

Question

A charged particle moving at an angle 30⁰ with an uniform magnetic field of 0.5 tesla. If the velocity of the charged particle is 10 m/s and its charge is 2C then force acting on it is

Easy

A

5 N
B

10N
C

50 N
D

2.5 N

Solution

Force on a charged particle in a magnetic field is $F = q (V \times B) = q V B \sin θ = 2 \times 10 \times 0.5 \times \frac{1}{2} = 5 N$

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