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Questions  

The circuit is equivalent to

a
AND gate
b
NAND gate
c
NOR gate
d
OR gate

detailed solution

Correct option is C

The gate circuit can be shown by giving two inputs A and BOutput of NOR gate, Y1=A + B    Output of NAND gate,   Y2 = Y1 . Y1 = A + B · A + B = A + B +A + B       =(A+B) + (A+B) =A+B Output of NOT gate, Y=Y2 = A+BWhich is the output of NOR gate.Alternative:

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