First slide

Internal energy

Question

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is :

Easy

A

$\frac{5}{2} R T$
B

$\frac{3}{2} R T$
C

$3 R T$
D

$\frac{9}{2} R T$

Solution

Degrees of freedom for a non linear triatomic molecule = Three Translation + Three Rotation = 6
(or) f=3A-B=3(3)-3=6 A=no. of atoms and B= no of restrictions
$U = \frac{f}{2} R T = \frac{6}{2} R T = 3 R T$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App